Question

Find the smallest number which when increase by 17 is exactlydivisble by 250 and 468

Answer 1

Answer:

Step-by-step explanation:

The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. LCM of 520 and 468 = 2 × 2 × 2 × 3 × 3 × 5 × 13 = 4680. Smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4680 17 = 4663

Answer 2

Answer:

Step-by-step explanation: