Question

Find the smallest number which when increased by 11 is exactly divisible by both 154 and 220.

Answer 1

Given:

• A smallest number increased by 11 is exactly divisible by both 154 and 220.

To Find:

• The smallest number.

Solution:

Let's assume smallest number is x

⇒        When increased by 11,

⇒        Number becomes ( x + 11)

This increased number exactly divisible by both 154 and 220.

So,

⇒                 x+11 is the LCM of 154 and 220

⇒                  LCM of 154 and 220  1540

Now,

⇒      $1540 = x + 11$

          $x = 1540 - 11$

          $x = 1529$

Thus, The smallest number is 1529.