Math, asked by ishamalhotra1927, 1 month ago

Find the smallest number which when increased by 12 is completely divisible by 168 and 261.

Answers

Answered by chintalasaikesh

1

Step-by-step explanation:

now add 12 to both no.s and find LCM i.e.

168+12 = 180 and 261+12=273

180= 2²x3²x5

273=3x7x13

LCM= 7x5x3²x2²x13

LCM= 16380

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