Question

find the smallest number which when increased by 13 is exactly divisible by both 480 and 366​

Answer 1

Answer:

First we need to find the L.C.M. of 520 and 468, since that will be the lowest number divisible both by 520 and 468. Then we need to reduce 17 from that number.

Prime factorisation of :-

520= 2 X 2 X 2 X 5 X 13 = 2^3 X 5 X 13

468 = 2 X 2 X 3 X 3 X 13= 2^2 X 3^2 X 13

So, L.C.M. = 2^3 X 5 X 13 X 3^2= 4680

So, the answer is 4680 - 17 = 4663.

Step-by-step explanation:

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