Question

Find the smallest number , which when increased by 17 , is exactly divisible by both 520 and 468.​

Answer 1

Answer:

4663

Step-by-step explanation:

Let the number be 'a'

given:

a+17 is divisible by 520 and 468

a +17 = LCM of 520 and 468

a+17 = 4680

a = 4680 - 17

a = 4663

Thanks

Answer 2

Answer:

HLO MATE

THE ANSWER IS:-

4663

calculated and gave

mark it as brainliest