Math, asked by aayushror, 9 months ago

Find the smallest number which when increased by 17 is exactly divisible by 468 and 520.

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Answered by kommerlachaitanyasai

Answer:

520 is the smallest number

Answered by Anonymous

Answer

The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4663.

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Find the smallest number which when increased by 17 is exactly divisible by 468 and 520.​

Answers

Find the smallest number which when increased by 17 is exactly divisible by 468 and 520.