Question

Find the smallest number which when increased by 17 is exactly divisible by both 520 and 468​

Answer 1

Answer:

yes

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Answer 2

Answer:

4663 is the answer

Step-by-step explanation:

The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4663.