Question

Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520​

Answer 1

Answer:

4663

The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4663.

Answer 2

Answer:

4663

Step-by-step explanation:

4663

The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4663.