Question

find the smallest number which when increased by 17 is exactly divisible by both 468 and 520

Answer 1

its 4663 bro..............

Answer 2

Answer:

4663

Step-by-step explanation:

Given :- 468 and 520

           smallest no =17

first find prime factorization of 468 and 520

468 = 2 x 2 x 3 x 3 x 13

520 =  2 x 2 x 2 x 5 x 13

L.C.M of 468,520 = 2 x 2 x 2 x 3 x 3 x 5 x 13

                             =4680

sub 4680 -17 = 4663

the smallest no is 4663