Question

find the smallest number which when increased by 17 is exactly divisible by both 468 and 520

Answer 1

Here is your answer...
Hope this will help you....

Answer 2

Step-by-step explanation:

The Least Common Multiple of 520 and 468 are ;-

$520 = 2 \times 2 \times 2 \times 5 \times 13$

$468 = 2 \times 2 \times 3 \times 3 \times 13$

$lcm=2×2×2×3×3×5×13$

Which is equal to = 4680

So The least Number Divisible by both 520 and 468 is 4680

Let the number increased by 17 gives the number divisible by 520 and 468 be x .

x + 17 = 4680x+17=4680

x = 4663x=4663

4663 is ur answer