find the smallest number which when increased by 17 is exactly divisible by both 520 and 468
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5
First find the LCM of 520 and 468
LCM OF 520 AND 468 IS 4680
4680 - 17 = 4663
so //// 4663 //// IS THE SMALLEST NUMBER WHICH WHEN INCREASED BY 17 IS EXACTLY DIVISIBLE BY BOTH 520 AND 468
LCM OF 520 AND 468 IS 4680
4680 - 17 = 4663
so //// 4663 //// IS THE SMALLEST NUMBER WHICH WHEN INCREASED BY 17 IS EXACTLY DIVISIBLE BY BOTH 520 AND 468
Anonymous:
why u subtracted 17
we get lcm as 4680 if we add 17 then it won't get divisible by both so we have to substract it .then we get a smallest number which divisible by both .
Answered by
3
LCM of 520 and 468 is = 4680
That means 4680 is divisible by 520 as well as 468
required number = 4680-17 = 4663
That means 4680 is divisible by 520 as well as 468
required number = 4680-17 = 4663
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