Question

find the smallest number which when increased by 17 is exactly divisible by both 520 and 468. plz do it it's urgent.

Answer 1

Solution:-
LCM of 520 and 468=2×2×2×3×3×5×13=4680
The number will be exactly divisible by 520and 468 when increased by 17 is
=4680-17
=4663

Answer 2

Hey ! ! !

Mate :-

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Question :-

☆ find the smallest number which when increased by 17 is exactly divisible by both 520 and 468. plz do it it's urgent.

Solution :-

☆ To find the number exactly divisible by both 520 and 468.

Find the lcm of Both Numbers ( 520 , 468 )

LCM = 4680

:-

☆ to find the number increased by 17

Subtract 17 fro it

:- 4680 - 17

= 4663.

So, least number divisible by both 520 and 468 is 4680.

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☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡