Math, asked by garvityadav230406, 10 months ago

find the smallest number which when increased by 20 is exactly divisible by both 520 and 468

Answers

Answered by Amr1tanshSingh

0

Answer:

4660

Step-by-step explanation:

Firstly,

Take LCM of 520 & 468

The LCM will come out to 4680.

Then,

Just subtract 20 from from 4680

You will get the answer, i.e. 4660

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