find the smallest number which when increased by 20 is exactly divisible by both 520 and 468
Answers
Answered by
0
Answer:
4660
Step-by-step explanation:
Firstly,
Take LCM of 520 & 468
The LCM will come out to 4680.
Then,
Just subtract 20 from from 4680
You will get the answer, i.e. 4660
Similar questions