Question

Find the smallest number which when increased by 3 is exactly divisible by 24, 36 and 60.

Answer 1

Answer:

357

Step-by-step explanation:

The least number that is divisible by all the three of these numbers is their LCM.

Let the LCM be x.

Suppose we subtract 3 from the LCM. Let it be x-3.

Let us add 3 to x-3.

We get x again. So the required number is x-3.

The LCM of 24, 36 and 60 is 360.

So x=360.

So x-3=357

Therefore, 357 is the smallest number which when increased by 3 is exactly divisible by 24, 36 and 60.

Hope it helps!!