Question

find the smallest number which when increased by 7 is exactly divisible by 75, 135, 189 and 252.​

Answer 1

Answer:

the LCM of 75,135,189 and 252. Subtract the answer by 7 and you'll get the answer...

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Answer 2

Answer:

The smallest number which when increased by 7 is exactly divisible by 75, 135, 189 and 252.

Step-by-step explanation:

To find the smallest number which when increased by 7 is exactly divisible by 75,135,189 and 252.

now taking the lcm of 75,135,189 and 252.

we get the number and then subtracting the 7 from the LCM we get our answer.

75=3*5*5

75=3*5*5135=3*5*3*3

75=3*5*5135=3*5*3*3189=3*3*3*7

75=3*5*5135=3*5*3*3189=3*3*3*7252=3*3*4*7

now LCM comes out to be 18900.

let the smallest number be 18900*n -7.

now put the value of n = 1,

we get,

=18900-7

=18893

this number is divisible by 75, 135, 189 and 252.

The smallest number which when increased by 7 is exactly divisible by 75, 135, 189 and 252 is 18893.

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