Math, asked by shubhamkumardubey955, 1 month ago

find the smallest number which when increased by 7 is exactly divisible by 75,135,189and 252​

Answers

Answered by vlogschinnus
0

Answer:

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Step-by-step explanation:

The given numbers are 520 and 468. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4663.

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