Question

find the smallest number which, when increased by one is exactly divisible by 12, 18, 24. 32 and 40.​

Answer 1

L.C.M. of given numbers So, L.C.M = 2 x 2 x 2 x 3 x 4 x 5 = 1440 = One increasing The required number = 1440 - 1 = 1439

Answer 2

Answer:

we have to see a common factor of the numbers and when they are divided, the r=1

so,

Take lcm of 12, 18,24,32

and add 1

lcm=1440

@dd 1

hope this helps u