Find the smallest number which when increases by 7 is exactly divisible by 6 and 32
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Answered by
2
Answer:
89✓
LCM of 6,32 is 96
96 is the smallest number which is divisible by 6 and 32....
96-7=89.
Answered by
4
Answer:
LCM of 6 ,32 is 96
96 - 7 = 89
89 is the smallest number which when increases by 7 is exactly divisible by 6 and 32
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