find the smallest number which when reduced by 2 become divisible by 24,48 and 64
Answers
Answered by
29
the smallest no is 194 because when we reduced it by2 then the answer is also 192
192/24=8
192/48=4
192/64=3
May be...
192/24=8
192/48=4
192/64=3
May be...
bhallasourabh3pc7eqp:
x+2-2=2 and HCF of 24,48 and 64 is 192 hence x=192 thus x+2=194
i did it
and thanks
thankuuu
suruchi... Ur answer is not correct
And ur wlcm
pls send details of hcf 24,48,64
Factorise them along
send pls
64×3
Answered by
19
the smallest no is 194 because when we reduced it by2 then the answer is also 192
192/24=8
192/48=4
192/64=3
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