Question

find the smallest number which when reduced by 2 becomes divisible by 24 and 48 and 64​

Answer 1

Answer:

Let the smallest number be x.

so in question they are tell that

(x-2)/24∈ positive integers ;

(x-2)/48∈ positive integers ;

(x-2)/64∈ positive integers ;

LCM of 24,48,64=64

so the smallest value of x which satisfies (x-2)/64 will be the answer

the smallest multiple of 64=1

so, (x-2)/64=1

x-2=64

x=64+2

x=66

Answer 2

Answer:

194.

Step-by-step explanation:

LCM of 24, 48, 64 = 192

Since, 2 is reduced from a number ; so to have the number, we will add this 2 to the LCM of the given numbers ( 24, 48, 64 ) ; i.e. ; 192.

=> 192 + 2 = 194 = the required number.

Hope it helps u !!!!!!!!