Question

Find the smallest number which when reduced by 2 becomes divisible by 24 48 and 64

Answer 1

Answer:

HERE YOU GO!!

Let the smallest number be x.

so in question they are tell that

(x-2)/24∈ positive integers ;

(x-2)/48∈ positive integers ;

(x-2)/64∈ positive integers ;

LCM of 24,48,64=64

so the smallest value of x which satisfies (x-2)/64 will be the answer

the smallest multiple of 64=1

so, (x-2)/64=1

x-2=64

x=64+2

x=66

HOPE IT HELPS

MARK AS BRAINLIEST