Math, asked by sk9431371, 1 month ago

Find the smallest number which when reduced by 2 becomes devisible by 24, 48 and 64.​

Answers

Answered by ladlym01
0

Answer:

the smallest no. divisible by 24,48and64 is the LCM of them which is 1536. now add 2 to it to get 1538 which is the answer.

Step-by-step explanation:

Answered by khushi110409
0

Answer:

1538

Step-by-step explanation:

The smallest no.divisible by 24,48and64 is the LCM of them which is 1536. now add 2 to it to get 1538 which is the answer.

Similar questions