Question

find the smallest number which when reduced by 3 is divisible by 21 and 28
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Answer 1

LET ME HELP YOU WITH IT MATE...

LET THAT NUMBER BE x.

THERE FORE,x-3=LCM(21,28)

HERE,WE HAVE 2 NUMBERS,21 & 28.

FACTORS OF 21=7 X 3

FACTORS OF 28= 7 X 2 X 2

THEREFORE,LCM(21,28)=7 X 2 X 2 X 3= 84

NOW,x-3=84

THEREFORE,x=84+3=87.

HENCE,THE REQUIRED NO. IS 87.

HOPE YOU ARE HELPED MATE.

PLEASE CONSIDER MARKING MY ANSWER AS BRAINLIEST....