find the smallest number which when reduced by 3 is divisible by 21 and 28
Answers
Answered by
0
LET ME HELP YOU WITH IT MATE...
LET THAT NUMBER BE x.
THERE FORE,x-3=LCM(21,28)
HERE,WE HAVE 2 NUMBERS,21 & 28.
FACTORS OF 21=7 X 3
FACTORS OF 28= 7 X 2 X 2
THEREFORE,LCM(21,28)=7 X 2 X 2 X 3= 84
NOW,x-3=84
THEREFORE,x=84+3=87.
HENCE,THE REQUIRED NO. IS 87.
HOPE YOU ARE HELPED MATE.
PLEASE CONSIDER MARKING MY ANSWER AS BRAINLIEST....
Similar questions
Social Sciences,
3 months ago
Social Sciences,
6 months ago
Science,
6 months ago
Biology,
10 months ago
English,
10 months ago