Question

find the smallest number which when reduced by 5 becomes divisible by 32 and 56 and 70

Answer 1

L.C.M.of 32,56 and 70 has to be first found.
2|32,56,70
7|16,28,35
2|16,4,5
2|8,2,5
|4,1,5=> least common multiple=2×7×2×2×4×5=1120
So the smallest number=1120+5=1125.