Question

Find the smallest number which when reduced by 5, is exactly divisible by 27 and 18 and 44

Answer 1

✰✰|| To Find ||✰✰

• smallest no. which when reduced by 5, is exactly divisible by 27 and 18 and 44

✪|| Solution ||✪

( LCM of 27, 18 and 44 ) + 5 = smallest number

→ 1188 + 5 = smallest number

→ 1123 = smallest number

1123 is no. when reduced by 5, is exactly divisible by 27, 18 and 44