find the smallest number which when we divide by 30 40 and 60 leaves the remainder 7 in each case
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lcm of 30,40,60 is 120
120 + 7=127
therefore 127 is the smallest number which when divided by 30,40 and 60 leaves a remainder of 7
120 + 7=127
therefore 127 is the smallest number which when divided by 30,40 and 60 leaves a remainder of 7
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