find the smallest number which when we divide by 30 40 and 60 leaves the remainder 7 in each case
Answers
Answered by
2
lcm of 30,40,60 is 120
120 + 7=127
therefore 127 is the smallest number which when divided by 30,40 and 60 leaves a remainder of 7
120 + 7=127
therefore 127 is the smallest number which when divided by 30,40 and 60 leaves a remainder of 7
rohit844:
there arelots more questions
Similar questions
Math,
8 months ago
Social Sciences,
8 months ago
Math,
1 year ago
Math,
1 year ago
English,
1 year ago