Question

② Find the smallest numbers which when reduced bý 2
becomes de visible by 24,48,64.​

Answer 1

Answer:

24=48

48=96

64=128

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Answer 2

Answer:

194

Step-by-step explanation

The smallest number divisible by 24,48,64 is the LCM of these 3 numbers

therefore,  LCM of 24,48,64 is 192

therefore, 194 is the smallest number when reduced by 2 i.e, 192 is divisible by these 3 numbers