find the smallest numbet by which 2187 must be divided to obtained a per fect cube
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3 । 2187
3 । 729
3 । 243
3 । 81
3 । 27
3 । 9
3 । 3
। 1
So, (3x3x3) (3x3x3) 3
3³x3³x3=2187
So,the smallest numbet by which 2187 must be divided to obtained a per fect cube is 3.
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