Math, asked by gauritanu125, 11 months ago

FIND THE SMALLEST PERFECT SQUARE DIVISIBLE BY 6,9 AND 15.

Answers

Answered by student0135

3

Step-by-step explanation:

LCM of 6,9 and 15 = 90 .

Resolving 90 into prime factor :-

90 = √2 × 3×3 × 5

90 = 3√10

Multiplying 90 into 10 = (90×10)

New number = 900

Hence the required smallest perfect square is 900

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