Question

Find the smallest perfect square, exactly divisible by each of the numbers 6,8,12 and 15. answer only if u know otherwise ignore

Answer 1

Answer:

3600

Step-by-step explanation:

Take LCM of (6,8,12 and 15) = 120

Resolving 120 into prime factors, we get

120 = 2*2*2*3*5

Here 2 is grouped in pairs of equal factors. But 2, 3 and 5 are not grouping in pairs of equal factors.

Let us multiply 2, 3 and 5 , we get a grouped in pairs of equal factors.

120*2*3*5 = 2*2*2*2*3*3*5*5

3600 = 2*2*2*2*3*3*5*5

Now 3600 is perfect square that is divisible by 6, 8, 12, and 15.

Answer 2

Take LCM of (6,8,12 and 15) = 120

Resolving 120 into prime factors, we get

120 = 2*2*2*3*5

Here 2 is grouped in pairs of equal factors. But 2, 3 and 5 are not grouping in pairs of equal factors.

Let us multiply 2, 3 and 5 , we get a grouped in pairs of equal factors.

120*2*3*5 = 2*2*2*2*3*3*5*5

3600 = 2*2*2*2*3*3*5*5

Now 3600 is perfect square that is divisible by 6, 8, 12, and 15.

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