find the smallest perfect square which is divisibal by 9,10,11 and also and find it's squre root
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Question :
find the smallest perfect square which is divisibal by 9,10,11 and also and find it's squre root
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Answer :
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Now, we will find out the prime factors of 990.
Prime factors of 990 = 2 × 3 × 3 × 5 × 11
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As we can see that prime factor 2,5 and 11 has no pair.
Therefore 990 must be multiplied by 2, 5 and 11 to make it a perfect square.
Therefore, the the smallest perfect square which is divisibal by 9,10 and 11 is 108900.
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