Math, asked by beenaadthakkar, 1 month ago

find the smallest perfect square which is divisibal by 9,10,11 and also and find it's squre root​

Answers

Answered by itzHeartySoul
4

Step-by-step explanation:

Question :

find the smallest perfect square which is divisibal by 9,10,11 and also and find it's squre root

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Answer :

\fbox\green{First  \: we  \: will \:  find \:  the  \: LCM  \: of \:  9,10,11.}

\bf\red{∴LCM  \: of \:  9,10  \: and \:  11 = 990}

Now, we will find out the prime factors of 990.

\begin{array}{r | l} 2 & 990 \\  3 & 495 \\ 3 & 165  \\ 5 & 55 \\ {11}  & 11 \\  & 1 \end{array}

Prime factors of 990 = 2 × 3 × 3 × 5 × 11

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As we can see that prime factor 2,5 and 11 has no pair.

Therefore 990 must be multiplied by 2, 5 and 11 to make it a perfect square.

\blue{∴ 990 × 2 × 5 × 11 = 1,08,900}

Therefore, the the smallest perfect square which is divisibal by 9,10 and 11 is 108900.

\bf\red{Square  \: root  \: of \:  108900 =  \sqrt{108900}  = 330}

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