find the smallest positive integer k such that 2^69+k is divisible by 127
Answers
Answered by
7
Step-by-step explanation:
Given find the smallest positive integer k such that 2^69+k is divisible by 127
- We need to find the smallest positive integer so that 2^69 + k is divisible by 127.
- Now 64 will be 2^7
- So 2^7 = 1 (mod 127)
- 2^7 p = 1^p = 1 (mod 127)
- Or 2^69 = 2^6 [ (2^7)^9]
- = 64 (mod 127)
- Now the minimum value of k will be 127 – 64 = 63
Reference link will be
https://brainly.in/question/4622183
Similar questions