Question

find the smallest positive integer k such that 2^69+k is divisible by 127​

Answer 1

Step-by-step explanation:

Given find the smallest positive integer k such that 2^69+k is divisible by 127

• We need to find the smallest positive integer so that 2^69 + k is divisible by 127.
•  Now 64 will be 2^7
•         So 2^7 = 1 (mod 127)
•              2^7 p = 1^p  = 1 (mod 127)
•           Or 2^69 = 2^6 [ (2^7)^9]
•                        = 64 (mod 127)
• Now the minimum value of k will be 127 – 64 = 63

Reference link will be

https://brainly.in/question/4622183