Math, asked by hotik37369, 9 months ago

Find the smallest possible integer,n, such that 198n is a perfect cube.

Answers

Answered by codiepienagoya
0

Given:

perfect cube of 198n

To find:

Find the smallest possible integer.

Solution:

Calculating the prime factor of 198:

\to 198= 2\times 3\times 3 \times 11\\\\

          = 2 \times 3^2\times 11

\to 198= 2\times 3^2 \times 11......(i)\\\\

In the given equation we have 198n. So prime factor of 198n:

\to 198n=2^n \times 3^n\times 11^n\\

if n= 3:

\to 198n=2^3 \times 3^3\times 11^3.......(ii)\\

divide the equation ii by i:

\to n= 2^2\times 3\times 11^2\\\\

       = 4\times 3\times 121\\\\=12\times 121\\\\=1452

The final value of n is: 1452

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