Question

Find the smallest prime number dividing the sum 3to the power of 11 and +5 to the power of 13​

Answer 1

the smallest prime no will be 2 divisible by the sum of 3 to the power of 11 and +5 to the power of 13

Explanation

Don't take it length do a little smart work since we know if we keep on multiplying the 11 with itself then the ones place digit must be 1 and same concept goes with 5 if we keep multiplying 5 with itself then the ones place digit must be 5

Therefore 5+1 = 6 which is divisible by 2 henceforth 2 is the smallest prime which can be divisible by the sum.

Hope it wud be helpful :)