Math, asked by kumarji4146, 11 months ago

find the smallest saqare number which is exactlydivisible by each of the number3,7,9,14,21

Answers

Answered by BKGGSS
0

Hello!

Here is your answer

the smallest number which is divisible by 3,7,9,14,21

3 = 3*1

7=7*1

9=3*3

14=7*2

21=7*3

multiplying 3,7,9,14,21

1^2 * 2^1 * 3^4 * 7^3

(p+1)(q+1)(r+1)

= (1+1)(4+1)(3+1)

= 2 * 5 * 4 = 40

40 factors

The smallest square number is 2^2 * 3^2 * 7^2= 1764

Similar questions