Find the smallest six digit number exactly divisible by 15,24 and 36
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hi There!
The smallest six digit number:
15= (3)*5
24= {(2*2)*2}* (3)
36= (2*2)* {(3)*3}
Smallest single digit number:
5*2*3* (3*2*2)= 360
See, what you have to do is find the COMMON terms and the uncommon ones.
You use the common terms only ONCE and multiply the other uncommon terms straight.
This is because the common terms are common in all or more than one, and would get REPEATED in the calculation. That way we avoid the repetition and then multiply the uncommon ones to get the number closest and divisible by all the Three numbers.
See the attached pic as well for aid..
Hope it helps!
The smallest six digit number:
15= (3)*5
24= {(2*2)*2}* (3)
36= (2*2)* {(3)*3}
Smallest single digit number:
5*2*3* (3*2*2)= 360
See, what you have to do is find the COMMON terms and the uncommon ones.
You use the common terms only ONCE and multiply the other uncommon terms straight.
This is because the common terms are common in all or more than one, and would get REPEATED in the calculation. That way we avoid the repetition and then multiply the uncommon ones to get the number closest and divisible by all the Three numbers.
See the attached pic as well for aid..
Hope it helps!
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harjwantsingh12:
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