find the smallest sqaure number which is divisible by 8,12 and 15
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8=238=23
12=22∗312=22∗3
15=3∗515=3∗5
20=22∗520=22∗5
So choosing the maximum of all the prime exponents that exist in the numbers above, we have,
LCM = 23∗3∗5=12023∗3∗5=120
Now, I will use an approach which others have not used to get to the least perfect square.
120 = 23∗3∗523∗3∗5
Now in a perfect square, ALWAYS, exponent of each prime is always even.
So, we will change the exponent of 2 from 3 to 4.
We will change the exponent of 3 from 1 to 2.
We will change the exponent of 5 from 1 to 2.
Finally we have the number 24∗32∗52=360024∗32∗52=3600.
So, required answer is 3600.
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Step-by-step explanation:
3600 is your answer
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