Question

find the smallest square no. that is divisible by each of the numbers of 8,15 and 20

Answer 1

What is the smallest square number that is divisible by 8, 15, and 20?
The first number divisible by 8, 15 and 20 will be their LCM i.e 120.

But on Factorising 120 we find that it's factors are not in pairs, whereas pairing is the first rule of finding a square or a square root of any number.

Factors of 120 are 2^3 × 3^1 × 5^1.

Here we see that each prime number needs one more power to become a pair so we increase each of their's exponential powers by one and get 2^4 × 3^2 × 5^2 which is equal to 3600.

And therefore we conclude that the smallest square number divisible by 8, 15 and 20 is 3600, which is the square of 60.

Answer 2

Answer:

3600

Step-by-step explanation:

step1= l.c.m= 2²×2×3×5= 120

step2= here 2, 3 and 5 ae not in pair

we have three no. so we will multiply them 2×3×5=30

so we will multiply 120 by 30=120×30=3600

so the smallest no is 3600 which is divisible by 8,15 and 20

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