find the smallest square number devisible by each of the numbers 8 , 9 and 10
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Answer:
Find the smallest square number divisible by each of the numbers 8 , 9 and 10
Smallest number divisible by 8,9 and 10
=L.C.M. of 8,9,10
2|8,9,10
...4,9,5
L.C.M.=2×4×9×5=360
Hence,the smallest number divisible by 8,9 and 10 is 360.
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The least square number which is exactly divisible by 8, 9, and 10 = L.C.M. of 8, 9, and 10.
Hence,L.C.M = 2×2×2×3×3×5=360
As we calculate,
2×2×2×3×3×5
2 and 5 have incomplete pairs.
So, to make if perfect square, we have to multiple it by
2 × 5 = 10
Now, 360 ×10 = 3600
Hence, the answer is 3600.
Hence,L.C.M = 2×2×2×3×3×5=360
As we calculate,
2×2×2×3×3×5
2 and 5 have incomplete pairs.
So, to make if perfect square, we have to multiple it by
2 × 5 = 10
Now, 360 ×10 = 3600
Hence, the answer is 3600.
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