Find the smallest square number divisible by each of the number 6,9 and 15
Answers
Answered by
6
Answer
Step-by-step explanation:
2_6,9,15
3_3,9,15
3_1,3,5
5_1,1,5
1_1,1,1
LCM(6,9,15)=2*3^2*5
So, smallest square number divisible by 6, 9 and 15 is 2^2*3^2*5^2=900
(Basically just squaring the factors of the LCM of 6, 9 and 15, if not already squared.)
Hope this helps you!!
Similar questions
Social Sciences,
1 year ago
Social Sciences,
1 year ago