Math, asked by aggarwalmonishka2008, 10 months ago

Find the smallest square number divisible by each of the number 6,9 and 15

Answers

Answered by neevlakhani11
6

Answer

Step-by-step explanation:

2_6,9,15

3_3,9,15

3_1,3,5

5_1,1,5

1_1,1,1

LCM(6,9,15)=2*3^2*5

So, smallest square number divisible by 6, 9 and 15 is 2^2*3^2*5^2=900

(Basically just squaring the factors of the LCM of 6, 9 and 15, if not already squared.)

Hope this helps you!!

Similar questions