Question

Find the smallest square number divisible by each of the numbers 5,8,12

Answer 1

Answer:

L.C.M. of 8, 15 and 20 is 120.

Prime factors of 120 = 2 x 2 x 2 x 3 x 5

Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.

\therefore120\times2\times3\times5=3600∴120×2×3×5=3600

Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600

Answer 2

Step-by-step explanation:

LCM of 5,8,12=120

2×2×2×5×3=120

here 2,3,5 have no pair.Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.

therefore 120 must be multipied to 2×2×5 make it a perfect square 120×2×3×5=3600

Hence, the smallest square number which is divisible by 8, 5 and 12 is 3600.