Question

find the smallest square number divisible by each one of the number 8,9and 10​

Answer 1

Answer:

3600 is the answer.

First, we need to find out the LCM of 8, 9 & 10.

LCM is 360

Prime factors of 360 = 2 × 2 × 2 × 3 × 3 × 5

2 and 5 are not in pairs. So we make them in pairs by multiplying by (2 × 5).

And we get,

360 × 10 = 3600

3600 satisfies both the conditions:

1. It is a square.
2. It is divisible by 8, 9 & 10

In fact, 3600 is the smallest square that is divisible by 8, 9 & 10.

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Answer 2

Answer:

1) first find the lcm of 8,9,10

2) after finding lcm..follow these steps

180=2×2×2×3×3×5

As the the pairs of 2 and 5 are not complete so we will multiply 180×2×5

180×2×5=2×3

required square no.=1080

Step-by-step explanation: