Find the smallest square number divisible by each one of the number 8,9,10
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Answered by
4
Answer:
L.C.M. of 8,9,10 is 2*2*2*3*3*5=360
Since 2 and 5 are not in pairs multiply by 2 and 5 to make it a perfect square.
The required number=360*2*5=3600
The smallest square number divisible by 8,9,10=3600.
i hope i will hlp u
Answered by
4
Answer:
LCM of 8, 9 and 10 is 2×2×2×3×3×5= 360.
Since, 2 and 5 are not in pairs,
We have to multiply both of them to make it a perfect square.
So, 360×2×5= 3600.
Therefore, the smallest square number divisible by 8, 9 and 10 is 3600.
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