Find the smallest square number divisible by each one of the numbers 8,9 and 10
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Answered by
551
hey the answer is ....
lcm = 360
so 2 × 2× 2 ×3 ×3× 5
2 and 5 r not grouped so u should multiply
2 ×5 = 10 to the lcm that is 360
so 360 x 10 = 3600
so the smallest number is 3600
hope it helps uu dear
lcm = 360
so 2 × 2× 2 ×3 ×3× 5
2 and 5 r not grouped so u should multiply
2 ×5 = 10 to the lcm that is 360
so 360 x 10 = 3600
so the smallest number is 3600
hope it helps uu dear
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Answered by
5
According to the question;
Take the LCM of 8, 9 and 10.
LCM of 8, 9 and 10 = 2×2×2×3×3×5
On grouping the LCM = (2×2) × (3×3) × 2 × 5, ( 2 and 5 are not able to make their pair)
so, to make it a perfect square, 360 must be multiplied by 2 × 5 = 10
360 × 10 = 3600.
The smallest square number divisible by each one of the numbers 8,9 and 10 is 3600.
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