Question

Find the smallest square number divisible by each one of the numbers 8,9 and 10

Answer 1

hey the answer is ....

lcm = 360

so 2 × 2× 2 ×3 ×3× 5

2 and 5 r not grouped so u should multiply
2 ×5 = 10 to the lcm that is 360

so 360 x 10 = 3600

so the smallest number is 3600

hope it helps uu dear

Answer 2

According to the question;

Take the LCM of 8, 9 and 10.

LCM of 8, 9 and 10 = 2×2×2×3×3×5

On grouping the LCM = (2×2) × (3×3) × 2 × 5, ( 2 and 5 are not able to make their pair)

so,  to make it a perfect square, 360 must be multiplied by 2 × 5 = 10

360 × 10 = 3600.

The smallest square number divisible by each one of the numbers 8,9 and 10 is 3600.

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