find the smallest square number is divisible by each of the number 8,15 and 20
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The number that is perfectly divisible by each of the numbers 8, 15, and 20 is their LCM. Here, prime factors 2, 3, and 5 do not have their respective pairs. Therefore, 120 is not a perfect square. Therefore, 120 should be multiplied by 2 × 3 × 5, i.e. 30, to obtain a perfect square.
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0
Answer:
I don't know how to do that ....I will try
Explanation:
815
+ 20
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