Math, asked by Niyu0412, 11 months ago

Find the smallest square number that is divisible by 6,18 and 21​

Answers

Answered by AJ3012
1

The smallest no divisible by these three no.s is 126 but since it is not a prfect square we are moving on.

We will start finding multiples of 126

126*1=126

126*2=252

126*3= 378

126*4=504

126*5=630

126*6=756

126*126= 15876

Hence the answer is 15876

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