Question

Find the smallest square number that is divisible by each of the number 2, 3, 6, 10

Answer 1

Step-by-step explanation:

First we have to find the LCM of 2,3,5,6 and 8

Then the LCM will be 120

By taking the prime factorization of 120

We get,

120=2×2×2×3×5 by taking these number in

a pair of two the number 2, 5 and 3 cannot be in pair

So we multiply the the whole number with 5 ,3 and 2.

So that we get each number in pair and by doing this we can get the perfect square root.

Now ,

2×2×2×3×5×3×5×2=3600

So the smallest square number divisible by

2,3,5,6 and 8 is 3600

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Answer 2

Answer:

the answer is 900 please follow me And Mark as branliest