Math, asked by prasunkumar3221, 8 months ago

Find the smallest square number that is divisible by each of the following numbers :
(ii) 6,9,27,36
(iii) 4,7,8,16

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Answers

Answered by sisterstherainbow
0

Answer:

hi mate here is your ans

but please full fill your promise

Step-by-step explanation:

i) 324

ii) 112

Answered by sarveshdsawant3
5

Answer:

(ii) 324

(iii)784

Step-by-step explanation:

(ii)First, we find the LCM of all these numbers.

LCM = 2 * 2 * 3 * 3 * 3 = 108

All square numbers have pairs of two similar factors in their prime factors

so,

(2 * 2) * (3 * 3) * (3) = 108

Therefore we multiply 108 by 3

(2 * 2) * (3 * 3) * (3 * 3) = 108 * 3 = 324

324 is the answer........

(iii)First, we find the LCM of all these numbers.

LCM= 2*2*2*2*7=112

All square numbers have pairs of two similar factors in their prime factors

so,

(2*2)*(2*2)*7=112

Therefore we multiply 112 by 7

(2*2)*(2*2)*(7*7)=112*7=784

784 is answer.....

pls mark as brainliest

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