Question

Find the smallest square number that is divisible by each of the numbers 5 , 8 and 10

Answer 1

Answer:

smallest square number divisible by 5 , 8 and 10 .= LCM of 5 , 8, 10.

=5×2×2×2

= 40

checking if 40 is a perfect square.

40 = 2×2×2×5

2 and 5 do not a perfect square

we multiply by 2 and 5 to make pairs

40×2×5 = 2×2×2×5×2×5

= 2×2×2×2×5×5

= 2×2×5

Now it becomes a perfect square

so , the required number is 400

ANSWER: 400

I hope this is helpful to you...

thank you

Answer 2

we will firstly take lcm of  5 , 8, 10.

= 40

now we will make 40  a perfect square by multiplying 10

thus the answer now is 400

which is exactly divisible by 5,8,10