Question

Find the smallest square number that is divisible by each of the numbers 8, 15 and 20

chapter-squares & square roots

note-please show the method ​

Answer 1

Answer:

3600

Step-by-step explanation:

the smallest number divisible by 8,15,20

is their L.C.M. i.e. 120

bit it's factorisation has no pairs of numbers and pair of number in the factorisation is the first condition to get a square number

120=5*3*(2^3)

observe there are no pair of 3 and 5 and only one pair of 2^2 , so to get the pairs of 5 and 3 and 2 multiply the number '120' by 5 and 3 and 2 it gives 120*5*3*2= 3600

hence the answer is 3600

it is the smallest square number divisible by 8,15,20.

as 3600=(5^2)*(3^2)*(2^2)*(2^2)

is a number having all factors as pairs